Berikut Conto ....
==========================================
|
Tahun
|
Point akhir (y)
|
x
|
x.y
|
X2
|
X4
|
X2Y
|
logY
|
X.LogY
|
|
2009-2010
|
96
|
-2
|
-192
|
4
|
16
|
384
|
1.982
|
-3.964
|
|
2010-2011
|
92
|
-1
|
-92
|
1
|
1
|
92
|
1.963
|
-1.963
|
|
2011-2012
|
100
|
0
|
0
|
0
|
0
|
0
|
2
|
0
|
|
2012-2013
|
85
|
1
|
85
|
1
|
1
|
85
|
1.934
|
1.934
|
|
2013-2014
|
87
|
2
|
174
|
4
|
16
|
348
|
1.939
|
3.878
|
|
Jumlah
|
460
|
|
-25
|
10
|
34
|
909
|
9.818
|
-0.115
|
|
a = ∑Y = 460 = 92
n 5
|
b = ∑XY = -25 = -2.5
X2 10
|
|
a = ∑Y.∑X4 - ∑X2Y. ∑X2
n.(∑X4) – (∑X2)2
= 460(34)
– 909(10)
5(34) - 102
= 15640
– 9090
170
– 100
= 6550
70
= 93.571
|
b = ∑XY
X2
= -25
10
= -2.5
|
c = n.∑X2Y - ∑X2. ∑Y
n.(∑X4) – (∑X2)2
= 5(909)
– 10(460)
5(34) - 102
= 4545
– 4600
170
– 100
= -55
70
= -0.786
|
|
a = Invers [ ∑logY ] atau
a = 10 ^ [ ∑logY ]
[ n
] [ n
]
= 10 ^ [9.818]
[ 5
]
= 10 ^ [1.963 ]
= 91.833
|
b = Invers [ ∑XlogY ] atau a = 10 ^ [ ∑XlogY
]
[ ∑X2
] [ ∑X2 ]
= 10 ^ [ -0.115 ]
[ 10
]
= 10 ^ [-0.0115 ]
= 0.973
|
|
y Linier
|
(y-y linier)2
|
y Kuadratis
|
(y-y Kuadratis)2
|
y Eksponensial
|
(y- y Eksponensial)2
|
|
97
|
1
|
95.427
|
0.328
|
-178.707
|
75463.95
|
|
94.5
|
6.25
|
95.285
|
10.791
|
-89.354
|
32889.1
|
|
92
|
64
|
93.571
|
41.332
|
0
|
10000
|
|
89.5
|
20.25
|
90.285
|
27.931
|
89.354
|
18.953
|
|
87
|
0
|
85.427
|
2.474
|
178.707
|
8410.177
|
|
460
|
91.5
|
459.995
|
82.856
|
0
|
126782.2
|
|
Jadi, persentase
point akhir real madrid pada tahun 2014-2015 diperkirakan dapat
mengumpulkan point 84.5,
yang merupakan hasil dari rumus y
Linier Y2014-2015 =
y
Linier = 92 + -2.5 X
= 92 + -2.5 (3)
= 84.5
|